@senya72 yup that is the other way. Something like:
cross_join(FEATURE as A,
<idx:int64>[feature_id=0:*,1000000,0]) as B,
I posted this mainly because I wanted the limit on number of expressions to be documented.
One reason for my quest to find this: it requires trivial AFL knowledge to generate the
filter query, and would be good for users who are new to AFL. The other uses
build with literal, chunk-sizes etc. i.e. a bit more knowledge is required.